2(x^2+24x-440)=0

Solution for 2(x^2+24x-440)=0 equation:

2(x^2+24x-440)=0

We multiply parentheses

2x^2+48x-880=0

a = 2; b = 48; c = -880;
Δ = b2-4ac
Δ = 482-4·2·(-880)
Δ = 9344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9344}=\sqrt{64*146}=\sqrt{64}*\sqrt{146}=8\sqrt{146}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-8\sqrt{146}}{2*2}=\frac{-48-8\sqrt{146}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+8\sqrt{146}}{2*2}=\frac{-48+8\sqrt{146}}{4}
$